第一个技巧,字符串转JSON
单条的json数据可以使用JObject.Parse将对象转化成JObject对象,你可以接着使用JsonConvert.SerializeObject方法把这个对象序列化后传到前台去
string Node = "{ id: 1, pId: 0, name: \"随意拖拽 1\", open: true }";
JObject jj = JObject.Parse(Node);
JArray.Parse可以用来讲json数组转成JArray对象,你可以接着使用JsonConvert.SerializeObject方法把这个对象序列化后传到前台去
string zNodes = "[ { id: 1, pId: 0, name: \"随意拖拽 1\", open: true }," +
"{ id: 11, pId: 1, name: \"随意拖拽 1-1\" }," +
"{ id: 12, pId: 1, name: \"随意拖拽 1-2\" }," +
"{ id: 121, pId: 12, name: \"随意拖拽 1-2-1\" }," +
"{ id: 122, pId: 12, name: \"随意拖拽 1-2-2\" }," +
"{ id: 123, pId: 12, name: \"随意拖拽 1-2-3\" }," +
"{ id: 13, pId: 1, name: \"禁止拖拽 1-3\", open: true, drag: false }," +
"{ id: 131, pId: 13, name: \"禁止拖拽 1-3-1\", drag: false }," +
"{ id: 132, pId: 13, name: \"禁止拖拽 1-3-2\", drag: false }," +
"{ id: 132, pId: 13, name: \"禁止拖拽 1-3-3\", drag: false }," +
"{ id: 2, pId: 0, name: \"禁止子节点移走 2\", open: true, childOuter: false }," +
"{ id: 21, pId: 2, name: \"我不想成为父节点 2-1\", dropInner: false }," +
"{ id: 22, pId: 2, name: \"我不要成为根节点 2-2\", dropRoot: false }," +
"{ id: 23, pId: 2, name: \"拖拽试试看 2-3\" }," +
"{ id: 3, pId: 0, name: \"禁止子节点排序/增加 3\", open: true, childOrder: false, dropInner: false }," +
"{ id: 31, pId: 3, name: \"随意拖拽 3-1\" }," +
"{ id: 32, pId: 3, name: \"随意拖拽 3-2\" }," +
"{ id: 33, pId: 3, name: \"随意拖拽 3-3\" }]";
JArray jsonObj = JArray.Parse(zNodes);

第二个技巧
自己拼凑的string字符串传递给前台的JS可能会因为符号问题出现错误,可以使用JObject对象和JArray对象转换一下再传递给前台就不会有问题了
