题目:http://poj.org/problem?id=1328 注意 输出 Case :这里是有个空格的。。和之前序列想法差不多 尽可能 向一边贪心。
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <stack>
#include <queue>
#include <vector>
#include <map>
#include <string>
#include <iostream>
using namespace std;
struct Node
{
double l;double r;
}node[11111];
double gao(double r,double x )
{
return sqrt(r*r-x*x);
}
int cmp(const Node &a,const Node &b)
{
return a.r<b.r;
}
int main()
{
int n,d;
//freopen("in.txt","r",stdin);
//freopen("out.txt","w",stdout);
double x,y;int sum=1;
while(scanf("%d%d",&n,&d),n||d){
int jiba=0;
for(int i=0;i<n;i++){
scanf("%lf%lf",&x,&y);
if(y>d||d<0||y<0){
jiba=1;continue;
}
double len=gao(d,y);
double l,r;
l=x-len;r=x+len;
node[i].l=l;node[i].r=r;
}
sort(node,node+n,cmp);
double ret[11111];
int ans=0;
for(int i=0;i<n;i++){
int flag=0;
for(int j=0;j<ans;j++){
if(node[i].l<=ret[j]&&node[i].r>=ret[j]){
flag=1;break;
}
}
if(!flag){
ret[ans++]=node[i].r;
}
}
printf("Case %d: ",sum++);
if(jiba)
printf("-1\n");
else
printf("%d\n",ans);
}
return 0;
}