castle ActiveRecord 初始化

最新推荐文章于 2021-02-15 15:55:24 发布

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最新推荐文章于 2021-02-15 15:55:24 发布

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原文链接：http://www.cnblogs.com/aji88/archive/2011/08/05/2128673.html

1.初始化单个实体类

ActiveRecordStarter.Initialize( source, typeof(User) );

2.初始化多个实体类

1.

ActiveRecordStarter.Initialize( source, typeof(Order),typeof(Product));

IConfigurationSource source = System.Configuration.ConfigurationManager.GetSection("activerecord") as     IConfigurationSource; 

Type[] paramTypes = new Type[3]; 
paramTypes[0] = typeof(User1); 
paramTypes[1] = typeof(Post); 
paramTypes[2] = typeof(Blog); 
ActiveRecordStarter.Initialize(source, paramTypes);

Assembly assembly = Assembly.Load("ARTest"); 
ActiveRecordStarter.Initialize(assembly, source);

  4.

// 获取数据库连接配置
XmlConfigurationSource source = new XmlConfigurationSource(@"Config\ActiveRecord.xml");

// 载入程序集中所有 ActiveRecord 类。
ActiveRecordStarter.Initialize(Assembly.GetExecutingAssembly(), source);

// 这样可以一次初始化所有的程序集里面的类。