Leetcode Two Sum II - Input array is sorted

本文介绍了一种解决有序数组中寻找两个数使其和为目标值的问题的方法。利用双指针技巧,从数组两端开始向中间搜索,根据当前两数之和与目标值的大小关系调整指针位置,直至找到正确答案。

Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number.

The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that your returned answers (both index1 and index2) are not zero-based.

You may assume that each input would have exactly one solution.

Input: numbers={2, 7, 11, 15}, target=9
Output: index1=1, index2=2


解题思路:

Without HashMap, just have two pointers, A points to index 0, B points to index len - 1, shrink the scope based on the value and target comparison.


Java code:

public class Solution {
    public int[] twoSum(int[] numbers, int target) {
        int left = 0;
        int right = numbers.length -1;
        while(left < right){
            int value = numbers[left] + numbers[right];
            if(value == target) {
                int[] result = {left+1, right+1};
                return result;
            }else if(value > target){
                right--;
            }else {
                left++;
            }
        }
        return null;
    }
}

Reference:

1. https://leetcode.com/discuss/19080/share-my-java-ac-solution

 

转载于:https://www.cnblogs.com/anne-vista/p/4886819.html

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