771. Jewels and Stones 珠宝和石头

本文介绍了一种算法,用于计算给定的石头中属于宝石的数量。输入包括两种类型的字符串:J表示宝石类型,S表示拥有的石头。通过对比S中的字符是否出现在J中来判断是否为宝石,并返回匹配字符的总数。

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You're given strings J representing the types of stones that are jewels, and S representing the stones you have.  Each character in S is a type of stone you have.  You want to know how many of the stones you have are also jewels.

The letters in J are guaranteed distinct, and all characters in J and S are letters. Letters are case sensitive, so "a" is considered a different type of stone from "A".

Example 1:

Input: J = "aA", S = "aAAbbbb"
Output: 3

Example 2:

Input: J = "z", S = "ZZ"
Output: 0

Note:

  • S and J will consist of letters and have length at most 50.
  • The characters in J are distinct.


   
  1. class Solution:
  2. def numJewelsInStones(self, J, S):
  3. """
  4. :type J: str
  5. :type S: str
  6. :rtype: int
  7. """
  8. res = 0
  9. s = set([(i) for i in J])
  10. for i in S:
  11. if i in s:
  12. res+=1
  13. return res





转载于:https://www.cnblogs.com/xiejunzhao/p/8379840.html

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