Codeforces 946 C.String Transformation

最新推荐文章于 2021-08-19 02:16:09 发布

转载最新推荐文章于 2021-08-19 02:16:09 发布 · 178 阅读

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原文链接：http://www.cnblogs.com/ZERO-/p/9711411.html

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#数据结构与算法

本文介绍了一个字符串转换的问题，目标是通过替换字符使给定字符串包含英语字母表作为子序列。提供了输入输出示例及代码实现。

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You are given a string s consisting of |s| small english letters.

In one move you can replace any character of this string to the next character in alphabetical order (a will be replaced with b, s will be replaced with t, etc.). You cannot replace letter z with any other letter.

Your target is to make some number of moves (not necessary minimal) to get string abcdefghijklmnopqrstuvwxyz (english alphabet) as a subsequence. Subsequence of the string is the string that is obtained by deleting characters at some positions. You need to print the string that will be obtained from the given string and will be contain english alphabet as a subsequence or say that it is impossible.

Input

The only one line of the input consisting of the string s consisting of |s| (1 ≤ |s| ≤ 105) small english letters.

Output

If you can get a string that can be obtained from the given string and will contain english alphabet as a subsequence, print it. Otherwise print «-1» (without quotes).

Examples

input

Copy

aacceeggiikkmmooqqssuuwwyy

output

abcdefghijklmnopqrstuvwxyz

input

Copy

thereisnoanswer

output

-1

代码:

 1 #include<iostream>
 2 #include<cstring>
 3 #include<cstdio>
 4 #include<cmath>
 5 #include<algorithm>
 6 #include<cstdlib>
 7 using namespace std;
 8 typedef long long ll;
 9 const int maxn=1e5+10;
10 #define ios ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
11 int main(){
12     string s;
13     ios;
14     cin>>s;
15     int len=s.length();
16     int tmp=0;
17     for(int i=0;i<len;i++){
18         if(s[i]-'a'<=tmp){
19             tmp++;s[i]='a'+tmp-1;
20         }
21         if(tmp==26)break;
22     }
23     if(tmp==26)cout<<s<<endl;
24     else cout<<"-1"<<endl;
25 }

溜了，滚去写D的题解。

转载于:https://www.cnblogs.com/ZERO-/p/9711411.html