leetcode 181 Employees Earning More Than Their Managers 不会分析的数据库复杂度

https://leetcode.com/problems/employees-earning-more-than-their-managers/description/

 

 

 

老师上课没分析这些的复杂度，我大概认为子查询要O（n^2）

一开始，直接用了子查询，2400ms....

# Write your MySQL query statement below
select T.name as Employee
from Employee as T
where T.Salary > (select Employee.salary from Employee where Employee.Id = T.ManagerId);

View Code

 

然后

标程有一个2000ms的，但我也认为他复杂度需要O（n^2）

SELECT
    a.Name AS 'Employee'
FROM
    Employee AS a,
    Employee AS b
WHERE
    a.ManagerId = b.Id
        AND a.Salary > b.Salary
;

 

最后一个用了join，确实理论上会比较快一丢丢，但是总体来说我感觉还是O（n^2）啊，1800ms快了很多很多

SELECT
    a.Name AS 'Employee'
From
    Employee as a join Employee as b
    on a.ManagerId = b.Id
where
    a.Salary > b.Salary
;

 

转载于:https://www.cnblogs.com/liuweimingcprogram/p/7890189.html