ZOJ 80ers' Memory

最新推荐文章于 2019-05-08 12:11:19 发布

转载最新推荐文章于 2019-05-08 12:11:19 发布 · 73 阅读

0 ·

CC 4.0 BY-SA版权

原文链接：http://www.cnblogs.com/dacc123/p/8228561.html

本文介绍了一道关于80后的记忆编程题目，主要涉及输入输出、字符串匹配等基本编程技能。题目要求从给定的80后关键词中识别并统计出测试用例中出现的关键词数量。

80ers' Memory

Time Limit: 1 Second Memory Limit: 32768 KB

I guess most of us are so called 80ers, which means that we were born in the 1980's. This group of people shared a lot of common memories. For example, the Saint Seiya, the YoYo ball, the Super Mario, and so on. Do you still remember these?

Input

There will be ONLY ONE test case.

The test case begins with a positive integer N, (N < 100).
Then there will be N lines each containing a single word describing a keyword of the typical 80ers' memories. Each word consists of letters, [a-zA-Z], numbers, [0-9], and the underline, '_'. The length of each word would be no more than 20.
Then one line follows with a positive integer K, (K < 100).
The last part of the test case will be K lines. The i-th line contains the keywords given by the i-th person and starts with a positive integer N_i. Then there will be N_i words separated by white spaces. Each of these words has no more than 20 characters.
All the words are case sensitive.

Output

For each of these K people, you are asked to count the number of typical 80ers' keywords on his/her list and output it in a single line.

Sample Input

4
Saint_Seiya
YoYo_ball
Super_Mario
HuLuWa
3
2 Saint_Seiya TiaoFangZi
1 KTV
3 HuLuWa YOYO_BALL YoYo_ball

Sample Output

1
0

#include <iostream>
#include <stdlib.h>
#include <stdio.h>
#include <algorithm>
#include <math.h>
#include <string.h>
#include <map>
#include <string>

using namespace std;
int n,k,m;
map<string,int> a;
string b[105];
int main()
{
    scanf("%d",&n);
    string s;
    for(int i=1;i<=n;i++)
    {
        cin>>s;
        a[s]=1;
    }
    scanf("%d",&k);
    int ans=0;
    for(int i=1;i<=k;i++)
    {
        ans=0;
        scanf("%d",&m);
        for(int j=1;j<=m;j++)
        {
            cin>>s;
            if(a[s]!=0)
                ans++;
        }
        printf("%d\n",ans);
    }
    return 0;
}

转载于:https://www.cnblogs.com/dacc123/p/8228561.html