A - Fox And Snake-优快云博客

本文介绍了一个简单的编程任务，即在给定的n行m列的表格中绘制一个蛇形图案。蛇形图案从左上角开始，按照特定的规则延伸。文章提供了具体的输入输出格式，并附带了AC代码实现。

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Problem description

Fox Ciel starts to learn programming. The first task is drawing a fox! However, that turns out to be too hard for a beginner, so she decides to draw a snake instead.

A snake is a pattern on a n by m table. Denote c-th cell of r-th row as (r, c). The tail of the snake is located at (1, 1), then it's body extends to (1, m), then goes down 2 rows to (3, m), then goes left to (3, 1) and so on.

Your task is to draw this snake for Fox Ciel: the empty cells should be represented as dot characters ('.') and the snake cells should be filled with number signs ('#').

Consider sample tests in order to understand the snake pattern.

Input

The only line contains two integers: n and m (3 ≤ n, m ≤ 50).

n is an odd number.

Output

Output n lines. Each line should contain a string consisting of m characters. Do not output spaces.

Examples

Input

3 3

Output

###
..#
###

Input

3 4

Output

####
...#
####

Input

5 3

Output

###
..#
###
#..
###

Input

9 9

Output

#########
........#
#########
#........
#########
........#
#########
#........
#########
解题思路：按规律输出，当i为奇数时，输出的一行全部为'#'；当i为偶数时，用flag做开关，交换输出两种格式，水过！
AC代码：

 1 #include<bits/stdc++.h>
 2 using namespace std;
 3 #define FOR(a,b,c) for(int i=a;i<=b;++i)printf("%c",c)
 4 int n,m;bool flag;
 5 int main(){
 6     cin>>n>>m;flag=false;
 7     for(int i=1;i<=n;++i){
 8         if(i%2)FOR(1,m,'#');
 9         else{
10             if(!flag){FOR(1,m-1,'.');cout<<'#';flag=true;}
11             else{cout<<'#';FOR(2,m,'.');flag=false;}
12         }
13         cout<<endl;
14     }
15     return 0;
16 }