题目1036：Old Bill------简单的模拟

AC的代码如下，未考虑效

#include<iostream>
using namespace std;

int main()
{
	int N;
	while(cin>>N)
	{
		int max=0;
		int f1,f2,i,j,x,y,z;
		cin>>x>>y>>z;
		for(i=1;i<=9;i++)
		for(j=0;j<=9;j++)
		{
			int sum=i*10000+x*1000+y*100+z*10+j;
			if (sum%N==0)
			    {
			    	int tem;
			    	tem=sum/N;
			    	if (max<tem)
					{
					    max=tem; f1=i;f2=j;
			    	}
			    	
			    }
		}
		if (max==0)  cout<<0<<endl;
		else cout<<f1<<" "<<f2<<" "<<max<<endl;
	}
	return 0;
} 

　　

转载于:https://www.cnblogs.com/jianrenguo/p/6443134.html