数组练习题A财务管理

  • 第一次看全英文的题,还是有点不舒服的感觉,还是用了翻译器
    Larry graduated this year and finally has a job. He's making a lot of money, but somehow never seems to have enough. Larry has decided that he needs to grab hold of his financial portfolio and solve his financing problems. The first step is to figure out what's been going on with his money. Larry has his bank account statements and wants to see how much money he has. Help Larry by writing a program to take his closing balance from each of the past twelve months and calculate his average account balance.

    Input
    The input will be twelve lines. Each line will contain the closing balance of his bank account for a particular month. Each number will be positive and displayed to the penny. No dollar sign will be included.

    Output
    The output will be a single number, the average (mean) of the closing balances for the twelve months. It will be rounded to the nearest penny, preceded immediately by a dollar sign, and followed by the end-of-line. There will be no other spaces or characters in the output

    Sample Input
    100.00
    489.12
    12454.12
    1234.10
    823.05
    109.20
    5.27
    1542.25
    839.18
    83.99
    1295.01
    1.75
    Sample Output
    $1581.42

代码样例:

#include<stdio.h>

#define N 12

int main()

{

double m=0,l;

double s[N];

int i;

for(i=0;i<N;i++)

{scanf("%lf\n",&s[i]);        

m=m+s[i];}

l=m/N;

printf("$");

printf("%.2lf",l);

return 0;

} 
  • 定义一个可以存放十二个数值的数组,循环累加,计算平均

转载于:https://www.cnblogs.com/xiao--liang/p/10243726.html

### Python 数组练习题示例 #### 示例 1:数组旋转 给定一个整型数组 `nums` 和一个非负整数 `k`,将数组中的元素向右移动 `k` 步。 ```python def rotate(nums, k): k = k % len(nums) # 处理k大于数组长度的情况 nums[:] = nums[-k:] + nums[:-k] # 将数组后k个元素移到前面 ``` 此函数接收两个参数:一个是待操作的列表 `nums`,另一个是非负整数 `k` 表示要旋转的位置数量。通过计算模运算来处理当 `k` 超过数组长度的情形,并利用切片技术实现数组部分元素位置互换[^4]。 #### 示例 2:两数组相减 定义一个方法用于执行两个相同大小的一维数组之间的逐项差分运算: ```python import numpy as np def subtract_arrays(array_a, array_b): result_array = [] for i in range(len(array_a)): difference = array_a[i] - array_b[i] result_array.append(difference) return result_array ``` 这段代码展示了如何遍历两个输入数组并创建一个新的结果数组存储每一对对应元素之差。当然也可以借助第三方库 NumPy 提供的功能简化这一过程[^2]。 #### 示例 3:字符串拼接优化 对于由多个单字符组成的列表形式表示的大数字串,按照特定规则重新排列这些字符使得最终形成的数值最大或最小化的问题可以通过自定义比较器解决: ```python from functools import cmp_to_key def largest_number(nums_str): def compare(x, y): if x+y > y+x: return -1 elif x+y < y+x: return 1 else: return 0 sorted_nums = sorted(nums_str, key=cmp_to_key(compare)) return ''.join(sorted_nums).lstrip('0') or '0' ``` 这里实现了基于字符串连接后的字典序对比逻辑来进行排序的方法,从而获得最优解方案之一[^3]。
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