杭电acm刷题(3):1062,Text Reverse ...

本文介绍了一种简单的算法,用于将输入的字符串中每个单词逆序输出。该算法使用C++实现,通过检测空格来区分不同的单词,并利用双指针技术完成逆序输出。

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Problem Description

Ignatius likes to write words in reverse way. Given a single line of text which is written by Ignatius, you should reverse all the words and then output them.

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains a single line with several words. There will be at most 1000 characters in a line.

Output

For each test case, you should output the text which is processed.

Sample Input

3
olleh !dlrow
m’I morf .udh
I ekil .mca

Sample Output

hello world!
I’m from hdu.
I like acm.

程序思路:

通过空格区分单词,每检测到一个空格更新指针,一个指向头的位置,一个指向尾的位置。

程序:

#include "iostream"
#include "string"
#include "stdio.h"

using namespace std;

int main()
{
    int T;
    string str;
    int len;
    int cnt = 0;
    int start, end;

    cin >> T;
    getchar();

    for (int i = 0;i < T;i++)
    {
        getline(cin, str);
        len = str.size();
        str[len] = ' ';

        start = 0;
        for (int j = 0;j < len + 1;j++)
        {
            if (str[j] == ' ')
            {
                end = j - 1;
                for (int n = end;n >= start;n--)
                    cout << str[n];
                start = j + 1;
                if(j!=len)
                    cout << ' ';
                else
                    cout << endl;
            }
        }
    }

    return 0;
}

补充:

由于每个空格检测一次,所以还需要在接收到的字符串的最后补上一个空格。程序思路不难,很容易搞懂。

转载于:https://www.cnblogs.com/xuhongbin/p/7134164.html

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