w5

 1.用列表+循环实现，并包装成函数

def pySum(n):
    a = list(range(n))
    b = list(range(0,5*n,5))
    c = []
    for i in range(len(a)):
        c.append(a[i]**2+b[i]**3)
     return (c)

print(pySum(10))

2.用numpy实现，并包装成函数

import numpy
a = numpy.arange(10)
b = numpy.arange(0,50,5)
c = a+b
print(a,b,c)

输出

3.对比两种方法实现的效率，给定一个较大的参数n，用运行函数前后的timedelta表示。

import sys
from datetime import datetime
def pySum(n):
    a = list(range(n))
    b = list(range(0,5*n,5))
    c = []
    for i in range(len(a)):
        c.append(a[i]**2+b[i]**3)
     return (c)

print(pySum(10))

import numpy
def npSum(n):
    a = numpy.arange(10)
    b = numpy.arange(0,50,5)
    c = a+b
    return c
print(npSum(10))

from datetime import datetime
start = datetime.now()
pySum(10000)
delta = datetime.now()-start
print(delta)

from datetime import datetime
start = datetime.now()
npSum(10000)
delta = datetime.now()-start
print(delta)

 

 

 

转载于:https://www.cnblogs.com/MINATSU/p/9722730.html