#a1,a2,a3 ,·····,an
#b1,b2,b3 ,·····,bn
#求:
#a1+b1,a2+b2,a3 +b3,·····+an+bn
#1、列表+循环 实现,并包装成一个函数
def pySum(n):
a = list(range(10))
b = list(range(0, 50, 5))
c = []
for i in range(len(a)):
c.append(a[i] ** 2 + b[i] ** 3)
return(c)
print(pySum(10))
import numpy
def npSum(n):
a = numpy.arange(10)
b = numpy.arange(0, 50, 5)
c = a + b
return(c)
print(npSum(10))
from datetime import datetime
start = datetime.now()
pySum(100000)
delta = datetime.now()-start
print(delta)
start= datetime.now()
npSum(100000)
delta = datetime.now()-start
print(delta)
运行结果: