ny 151 Biorhythms

本文探讨了一个关于生物节律的问题,即找出从指定日期到下一个三个周期(物理、情绪、智力)峰值同时出现的日子之间的天数。通过数学计算确定了这一特定日期。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

Biorhythms

时间限制:1000 ms  |  内存限制:65535 KB
难度:3
 
描述

Some people believe that there are three cycles in a person's life that start the day he or she is born. These three cycles are the physical, emotional, and intellectual cycles, and they have periods of lengths 23, 28, and 33 days, respectively. There is one peak in each period of a cycle. At the peak of a cycle, a person performs at his or her best in the corresponding field (physical, emotional or mental). For example, if it is the mental curve, thought processes will be sharper and concentration will be easier. 
Since the three cycles have different periods, the peaks of the three cycles generally occur at different times. We would like to determine when a triple peak occurs (the peaks of all three cycles occur in the same day) for any person. For each cycle, you will be given the number of days from the beginning of the current year at which one of its peaks (not necessarily the first) occurs. You will also be given a date expressed as the number of days from the beginning of the current year. You task is to determine the number of days from the given date to the next triple peak. The given date is not counted. For example, if the given date is 10 and the next triple peak occurs on day 12, the answer is 2, not 3. If a triple peak occurs on the given date, you should give the number of days to the next occurrence of a triple peak. 

 
输入
You will be given at most 1000000 cases. The input for each case consists of one line of four integers p, e, i, and d. The values p, e, and i are the number of days from the beginning of the current year at which the physical, emotional, and intellectual cycles peak, respectively. The value d is the given date and may be smaller than any of p, e, or i. All values are non-negative and at most 365, and you may assume that a triple peak will occur within 21252 days of the given date. The end of input is indicated by a line in which p = e = i = d = -1
输出
For each test case, print the number of days to the next triple peak, in the form: 
样例输入
0 0 0 0
0 0 0 100
5 20 34 325
4 5 6 7
283 102 23 320
203 301 203 40
-1 -1 -1 -1
样例输出
21252
21152
19575
16994
8910
10789

题目大意:

  输入p,e,i(分别表示三个周期的峰值出现在该年的第p天、第e天、第i天),d 表示该年的第d天。求从这一天开始到 下一次出现三个周期的峰值
出现在同一天 所经历的天数。题目给出三个周期的长度分别为23,28,33

View Code
#include <stdio.h>
int main()
{
    int p,e,i,d,n;
    while(scanf("%d%d%d%d",&p,&e,&i,&d) && (p!=-1 || e!=-1 || i!=-1 || d!=-1))
    {
        n=(5544*p+14421*e+1288*i-d)%21252;
        if(n<=0) n+=21252;
        printf("%d\n",n);
    }
}

 

转载于:https://www.cnblogs.com/luosw/archive/2012/08/14/2637803.html

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值