POJ 2632 Crashing Robots

本文介绍了一个关于机器人在仓库中移动并避免碰撞的问题。通过定义机器人的位置、方向及指令,解决机器人是否会撞墙或互相碰撞的问题。使用Java实现了解决方案。

Crashing Robots http://acm.pku.edu.cn/JudgeOnline/problem?id=2632

Time Limit: 1000MS
Memory Limit: 65536K

Total Submissions: 3006
Accepted: 1328

Description

In a modernized warehouse, robots are used to fetch the goods. Careful planning is needed to ensure that the robots reach their destinations without crashing into each other. Of course, all warehouses are rectangular, and all robots occupy a circular floor space with a diameter of 1 meter. Assume there are N robots, numbered from 1 through N. You will get to know the position and orientation of each robot, and all the instructions, which are carefully (and mindlessly) followed by the robots. Instructions are processed in the order they come. No two robots move simultaneously; a robot always completes its move before the next one starts moving.
A robot crashes with a wall if it attempts to move outside the area of the warehouse, and two robots crash with each other if they ever try to occupy the same spot.

Input

The first line of input is K, the number of test cases. Each test case starts with one line consisting of two integers, 1 <= A, B <= 100, giving the size of the warehouse in meters. A is the length in the EW-direction, and B in the NS-direction.
The second line contains two integers, 1 <= N, M <= 100, denoting the numbers of robots and instructions respectively.
Then follow N lines with two integers, 1 <= Xi <= A, 1 <= Yi <= B and one letter (N, S, E or W), giving the starting position and direction of each robot, in order from 1 through N. No two robots start at the same position.

2632_1.jpg
Figure 1: The starting positions of the robots in the sample warehouse

Finally there are M lines, giving the instructions in sequential order.
An instruction has the following format:
< robot #> < action> < repeat>
Where is one of

  • L: turn left 90 degrees,
  • R: turn right 90 degrees, or
  • F: move forward one meter,

and 1 <= < repeat> <= 100 is the number of times the robot should perform this single move.

Output

Output one line for each test case:

  • Robot i crashes into the wall, if robot i crashes into a wall. (A robot crashes into a wall if Xi = 0, Xi = A + 1, Yi = 0 or Yi = B + 1.)
  • Robot i crashes into robot j, if robots i and j crash, and i is the moving robot.
  • OK, if no crashing occurs.

Only the first crash is to be reported.

Sample Input

4
5 4
2 2
1 1 E
5 4 W
1 F 7
2 F 7
5 4
2 4
1 1 E
5 4 W
1 F 3
2 F 1
1 L 1
1 F 3
5 4
2 2
1 1 E
5 4 W
1 L 96
1 F 2
5 4
2 3
1 1 E
5 4 W
1 F 4
1 L 1
1 F 20

Sample Output

Robot 1 crashes into the wall
Robot 1 crashes into robot 2
OK
Robot 1 crashes into robot 2

 

-------------------------------------------------------------

Solution

 
import java.util.Scanner;

enum Direction {
	N, S, W, E
}

class Robot {
	int id;
	int x;
	int y;
	Direction direction;

	public Robot(int i, int x, int y, String direction) {
		this.id = i;
		this.x = x;
		this.y = y;
		if (direction.equalsIgnoreCase("N"))
			this.direction = Direction.N;
		else if (direction.equalsIgnoreCase("S"))
			this.direction = Direction.S;
		else if (direction.equalsIgnoreCase("W"))
			this.direction = Direction.W;
		else if (direction.equalsIgnoreCase("E"))
			this.direction = Direction.E;
	}

	public void move(String command) {
		if (command.equalsIgnoreCase("F")) {
			switch (this.direction) {
			case N:
				this.y++;
				break;
			case S:
				this.y--;
				break;
			case W:
				this.x--;
				break;
			case E:
				this.x++;
				break;
			}
		} else {
			this.rotate(command);
		}
	}

	public void rotate(String s) {
		if (s.equalsIgnoreCase("L")) {
			switch (this.direction) {
			case N:
				this.direction = Direction.W;
				break;
			case S:
				this.direction = Direction.E;
				break;
			case W:
				this.direction = Direction.S;
				break;
			case E:
				this.direction = Direction.N;
				break;
			}
		} else {
			switch (this.direction) {
			case N:
				this.direction = Direction.E;
				break;
			case S:
				this.direction = Direction.W;
				break;
			case W:
				this.direction = Direction.N;
				break;
			case E:
				this.direction = Direction.S;
				break;
			}
		}
	}
}

public class POJ_2632 {

	public static String collision(Robot[] robots, Robot r, int x_dim, int y_dim) {
		int num = robots.length;
		if (r.x <= 0 || r.x > x_dim || r.y <= 0 || r.y > y_dim) {
			return "Robot " + r.id + " crashes into the wall";
		}
		for (int i = 0; i < num; i++) {
			if (r.x == robots[i].x && r.y == robots[i].y
					&& r.id != robots[i].id) {
				return "Robot " + r.id + " crashes into " + "robot "
						+ robots[i].id;
			}
		}
		return "OK";
	}

	public static void main(String[] args) {

		Scanner in = new Scanner(System.in);
		int rounds = in.nextInt();
		for (int i = 0; i < rounds; i++) {
			int x_dimension = in.nextInt();
			int y_dimension = in.nextInt();
			int num_robots = in.nextInt();
			String response = "OK", temp;
			Robot robots[] = new Robot[num_robots];
			int num_ins = in.nextInt();
			for (int j = 1; j < num_robots + 1; j++) {
				robots[j - 1] = new Robot(j, in.nextInt(), in.nextInt(), in
						.next());
			}
			for (int k = 0; k < num_ins; k++) {
				int r_id = in.nextInt();
				String command = in.next();
				int num_iteration = in.nextInt();
				Robot robot = robots[r_id - 1];
				for (int m = 0; m < num_iteration; m++) {
					robot.move(command);
					temp = collision(robots, robot, x_dimension, y_dimension);
					if (response.startsWith("O") && !temp.startsWith("O"))
						response = temp;
				}
			}
			System.out.println(response);
		}
	}

}

转载于:https://www.cnblogs.com/absjustin/archive/2010/01/15/1648231.html

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值