死锁与递归锁

最新推荐文章于 2025-07-06 16:03:34 发布

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最新推荐文章于 2025-07-06 16:03:34 发布

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原文链接：http://www.cnblogs.com/52-qq/p/7453148.html

本文通过Python threading模块的Lock和RLock类演示了多线程环境下死锁的发生及递归锁的使用方法。代码示例展示了两个线程分别尝试获取不同锁的顺序，从而引发死锁的情况，并通过递归锁解决该问题。

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from threading import Thread,Lock
import time
mutexA=Lock()
mutexB=Lock()

class MyThread(Thread):
    def run(self):
        self.func1()
        self.func2()
    def func1(self):
        mutexA.acquire()
        print('\033[41m%s 拿到A锁\033[0m' %self.name)

        mutexB.acquire()
        print('\033[42m%s 拿到B锁\033[0m' %self.name)
        mutexB.release()

        mutexA.release()

    def func2(self):
        mutexB.acquire()
        print('\033[43m%s 拿到B锁\033[0m' %self.name)
        time.sleep(2)

        mutexA.acquire()
        print('\033[44m%s 拿到A锁\033[0m' %self.name)
        mutexA.release()

        mutexB.release()

if __name__ == '__main__':
    for i in range(10):
        t=MyThread()
        t.start()

　　死锁↑ 递归锁↓

from threading import Lock,Thread,RLock
import time
mutexB=mutexA=RLock()       #同一把锁锁
class MyThread(Thread):
    def run(self):
        self.f1()
        self.f2()
    def f1(self):
        mutexA.acquire()
        print('拿到A锁',self.name)
        mutexB.acquire()
        print('拿到B锁',self.name)
        mutexB.release()
        mutexA.release()
    def f2(self):
        mutexB.acquire()
        print('拿到B锁', self.name)
        mutexA.acquire()
        print('拿到A锁', self.name)
        mutexA.release()
        mutexB.release()
if __name__ == '__main__':
    for i in range(10):
        t = MyThread()
        t.start()

转载于:https://www.cnblogs.com/52-qq/p/7453148.html