235. Lowest Common Ancestor of a Binary Search Tree

二叉搜索树最低公共祖先
本文介绍了一种在二叉搜索树中寻找两个指定节点的最低公共祖先的有效方法,并提供了一个简洁的Java实现示例。

题目:

Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST.

According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (where we allow a node to be a descendant of itself).”

        _______6______
       /              \
    ___2__          ___8__
   /      \        /      \
   0      _4       7       9
         /  \
         3   5

For example, the lowest common ancestor (LCA) of nodes 2 and 8 is 6. Another example is LCA of nodes 2 and 4 is 2, since a node can be a descendant of itself according to the LCA definition.

链接:  http://leetcode.com/problems/lowest-common-ancestor-of-a-binary-search-tree/

注意第4,5行的判断不要错

1 public class Solution {
2     public TreeNode lowestCommonAncestor(TreeNode root, TreeNode p, TreeNode q) {
3         if (root == null || p == null || q == null) return null;
4         if (root.val < p.val && root.val < q.val) return lowestCommonAncestor(root.right, p, q);
5         else if (root.val > p.val && root.val > q.val) return lowestCommonAncestor(root.left, p, q);
6         else return root;
7     }
8 }

 

转载于:https://www.cnblogs.com/panini/p/6493583.html

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值