Hamilton

import java.util.Vector;

class Hamilton
{
	int start;
	int a[][];
	int len;
	int x[];  // 记录回路
	boolean flag;
	
	public Hamilton(int[][] a, int n, int start)
	{
		this.a = a;
		this.len = n;
		this.flag = false;
		this.x = new int[n];
		this.start = start - 1;
	}

	public boolean isComplete(int k)
	{
		return a[x[k - 1]][x[0]] == 1;
	}

	public Vector<Integer> makeIterms(int k)
	{
		Vector<Integer> iterms = new Vector<Integer>();
		if (k == 0)
		{
			iterms.add(start);
		} else
		{
			for (int i = 0; i < len; i++)
				if (a[x[k - 1]][i] == 1)  // 相当重要
					iterms.add(i);
		}
		return iterms;  // 第k-1层结点的所有临界点
	}

	public void printSolution(int k)
	{
		System.out.print(x[0] + 1);
		for (int i = 1; i < len; i++)
			System.out.print("->" + (x[i] + 1));
		System.out.println("->" + (x[0] + 1));
	}

	public boolean isPartial(int k)
	{
		for (int i = 0; i < k; i++)
			if (x[i] == x[k])
				return false;
		return true;
	}
}

class General
{
//	回溯算法的引导框架
	public static void backtrack(Hamilton p)
	{
		explore(p, 0);
		if (!p.flag)
			System.out.println("no sulution!");
	}
//	回溯算法的探索框架
	private static void explore(Hamilton p, int k)
	{
		if (k >= p.len)
		{
			if (p.isComplete(k))
			{
				p.flag = true;
				p.printSolution(k);
			}
			return;
		}
		Vector<Integer> iterms = p.makeIterms(k);
		for (int i = 0; i < iterms.size(); i++)
		{
			p.x[k] = iterms.get(i);
			if (p.isPartial(k))
				explore(p, k + 1);
		}
	}

}

public class Test
{
	
	public static void main(String args[])
	{
		int c[][] = { { 0, 1, 1, 1, 0 }, { 1, 0, 1, 0, 1 }, { 1, 1, 0, 1, 0 },
				{ 1, 0, 1, 0, 1 }, { 0, 1, 0, 1, 0 } };

                Hamilton p;
		p = new Hamilton(c, 5, 1);
		General.backtrack(p);
	}
}

转载于:https://www.cnblogs.com/jiangu66/p/3190065.html