PTA-1005—— Spell It Right-优快云博客

本文介绍了一个处理大整数加法并将其各数位之和以英文单词形式输出的C++程序实现。文章详细展示了如何通过逐位累加的方式处理大整数，并在遇到进位时进行相应的调整，最后将得到的数位和转换成英文单词输出。特别注意了输入为0的特殊情况。

题目：

Given a non-negative integer

Input Specification:

Each input file contains one test case. Each case occupies one line which contains an

Output Specification:

For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.

Sample Input:

Sample Output:

one five

题目分析:

加数只有1位的大整数加法，但要考虑输入为0的特殊情况

代码:

 1 #include<iostream>
 2 #include<cstring>
 3 using namespace std;
 4 int ans[110];
 5 string number[10]={"zero","one","two","three","four",
 6                     "five","six","seven","eight","nine"};
 7 string s;
 8 int main(){
 9     cin>>s;
10     memset(ans,0,sizeof(ans));
11     for(int i=0;i<s.length();i++){
12         ans[0]+=s[i]-'0';
13         for(int j=0;j<s.length();j++){
14             if(ans[j]>=10){
15                 ans[j]-=10;
16                 ans[j+1]+=1;
17             }
18         }
19     }
20     bool flag=false;
21     for(int i=s.length()-1;i>=0;i--){
22         if(ans[i]!=0||flag){
23             flag=true;
24             if(i==0){
25                 cout<<number[ans[i]];
26             }else{
27                 cout<<number[ans[i]]<<" ";
28             }
29         }
30     }
31     if(!flag){            //一个特殊情况需要考虑：当输入为0时 
32         cout<<"zero";
33     }
34     return 0;
35 }