多维列表按序求和问题

最新推荐文章于 2025-05-09 17:56:07 发布

转载最新推荐文章于 2025-05-09 17:56:07 发布 · 198 阅读

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原文链接：http://www.cnblogs.com/standby/p/9353692.html

文章标签：

#python

Question

有如下一个字典，内嵌多维列表：

dic = {
  'hit_410000':[[1,11,21],[2,12,22]],
  'pku_410000':[[100,200,300],[200,400,600]],
  'hit_420000':[[3,13,23],[4,14,24]],
  'hit_430000':[[5,15,25],[6,16,26]],
}

请把所有以 'hit' 开头的key所对应的list按顺序求和，示例结果：{ 'hit':[[9, 39, 69], [12, 42, 72]] }

Answer

#!/usr/bin/python2.7

dic = {
  'hit_410000':[[1,11,21],[2,12,22]],
  'pku_410000':[[100,200,300],[200,400,600]],
  'hit_420000':[[3,13,23],[4,14,24]],
  'hit_430000':[[5,15,25],[6,16,26]],
}

# 首先获取 'hit' 开头的list 
new_dic = {}
for k,lst in dic.items():
    prefix,code = k.split('_')
    if prefix not in new_dic:
        new_dic[prefix] = [lst]
    else:
        new_dic[prefix].append(lst)
hit_lst = new_dic['hit'] if 'hit' in new_dic else None

# 把多维list转化成字典形式：
# {0: [[1, 11, 21], [3, 13, 23], [5, 15, 25]], 1: [[2, 12, 22], [4, 14, 24], [6, 16, 26]]}
tmp = {}
for i in range(len(hit_lst)):
    lst = hit_lst[i]
    for j in range(len(lst)):
        if j not in tmp:
            tmp[j] = []
        tmp[j].append(lst[j])

# 使用reduce结合lambda表达式求和
length = 3
final_res = []
for _,lst in tmp.items():
    sums = reduce(lambda x,y:[x[i]+y[i] for i in range(length)], lst, [0]*length)    
    final_res.append(sums)

print final_res

# 结果：[[9, 39, 69], [12, 42, 72]]

转载于:https://www.cnblogs.com/standby/p/9353692.html