得到下一秒的日期和时间并计算是第几天

最新推荐文章于 2022-04-15 15:15:04 发布

转载最新推荐文章于 2022-04-15 15:15:04 发布 · 55 阅读

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原文链接：http://www.cnblogs.com/this-543273659/archive/2011/07/31/2122913.html

本文通过两种方法实现了C++中的日期类，包括日期的递增运算，并计算了一年中当前日期的位置。第一种方法使用了面向对象的设计，定义了一个date类；第二种方法则直接使用函数来实现相同的功能。

推荐方法一，方法二本人所写，给方法一比较简直就是刚学C 而且C也没学好，不会C++，面向对象的思想真不是一撮而就的事啊！我需要更加努力！加油。。。。。。。

方法一：

#include<iostream.h>

#include<stdio.h>

class date

{

private:

int m_nYear, m_nMonth, m_nDay, m_nHour, m_nMin, m_nSec;

int GetDay(int month);

bool IsLeapYear();

public:

date(int,int,int,int,int,int);

const date GetNextDate();

void printDate();

int FindDayIndex();

};

date::date(int year, int month, int day, int hour, int min, int sec)

{

this->m_nYear = year;

this->m_nMonth = month;

this->m_nDay = day;

this->m_nHour = hour;

this->m_nMin = min;

this->m_nSec = sec;

}

bool date::IsLeapYear()

{

if((m_nYear % 400 == 0) || (m_nYear % 4 == 0 && m_nYear % 100 != 0))

return true;

else

return false;

}

int date::GetDay(int month)

{

int day;

switch(month)

{

case 1:

case 3:

case 5:

case 7:

case 8:

case 10:

case 12:

day = 31;

break;

case 2:

if(IsLeapYear())

day = 29;

else

day = 28;

break;

default:

day = 30;

}

return day;

}

const date date:: GetNextDate()

{

date dat = *this;

if(dat.m_nSec != 59)

dat.m_nSec ++;

else

{

dat.m_nSec = 0;

dat.m_nMin += 1;

}

if(dat.m_nMin == 60)

{

dat.m_nHour += 1;

dat.m_nMin = 0;

}

if(dat.m_nHour == 24)

{

dat.m_nDay += 1;

dat.m_nHour = 0;

}

if(dat.m_nDay == dat.GetDay(this->m_nMonth) + 1)

{

dat.m_nDay = 1;

dat.m_nMonth += 1;

}

if(dat.m_nMonth == 13)

{

dat.m_nMonth = 1;

dat.m_nYear += 1;

}

return dat;

}

int date::FindDayIndex()

{

int totalDay = 0;

for(int i = 1; i < m_nMonth; i++)

totalDay += GetDay(i);

totalDay += m_nDay;

return totalDay;

}

void date::printDate()

{

cout<<m_nYear<<"-"<<m_nMonth<<"-"<<m_nDay<<" "<<m_nHour<<":"<<m_nMin

<<":"<<m_nSec<<endl

<<"这是"<<m_nYear<<"年的第"<<FindDayIndex()<<"天"<<endl;

}

int main()

{

cout<<"请输入一个日期,格式如：2002-5-8 11:23:59"<<endl;

int year, month, day, hour, min, sec;

scanf("%d-%d-%d %d:%d:%d",&year, &month, &day, &hour, &min, &sec);

date dat(year, month, day, hour, min, sec);

date nextDat = dat.GetNextDate();

nextDat.printDate();

}

方法二：

#include<iostream>
using namespace std;
bool isleapYear(int year)
{
if((year%4==0&&year%100!=0)||(year%400==0))
return true;
else return false;

}
int getDay(int month,int year)
{
int day;
switch(month)
{
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12: day=31;break;
case 2:
  if(isleapYear(year))
   day=29;
  else day=28;
  break;
default: day=30;
}
return day;

}
void count(int year,int month,int day)
{

int Cday=0;
while(month--!=0)
   Cday+=getDay(month,year);
Cday+=day;
cout<<"今天是今年的第"<<Cday<<"天"<<endl;
}
void getNext(int second,int minute,int hour,int day,int month,int year)
{
if(second!=59)
  second++;
else
{
  second=0;
  minute++;
}
if(minute==60)
{
  minute=0;
  hour++;
}
if(hour==25)
{
  hour=1;
  day++;
}
if(day==getDay(month,year)+1)
{
  day=1;
  month++;
}
if(month==13)
{
  month=1;
  year++;
}
cout<<year<<"-"<<month<<"-"<<day<<"     "<<hour<<":"<<minute<<":"<<second<<endl;
count(year,month,day);

}
int main()
{
int year=2000;
int month=2;
int day=28;
int hour=24;
int minute=59;
int second=59;
getNext(second,minute,hour,day,month,year);
}

转载于:https://www.cnblogs.com/this-543273659/archive/2011/07/31/2122913.html