C# 根据地址调用 Google Map 服务得到经纬度

最新推荐文章于 2022-04-09 18:29:30 发布

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最新推荐文章于 2022-04-09 18:29:30 发布

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CC 4.0 BY-SA版权

文章标签： c#

原文链接：http://www.cnblogs.com/Music/archive/2012/12/18/get-lat-and-lng-by-invoke-google-map-web-service-in-c-sharp.html

本文介绍如何使用C#语言通过调用Google地图Web服务API来获取给定邮政编码对应的经纬度信息，包括实现过程、关键代码解析及异常处理。

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直接贴代码了：

using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Net;
using System.Text;
using System.Web.Script.Serialization;

namespace MvcUI.Extensions
{
    public static class LocalisationUtils
    {
        /// <summary>
        /// 根据地址调用 Google 服务得到经纬度
        /// </summary>
        /// <param name="postcode"></param>
        /// <returns></returns>
        public static List<string> GeocodeGoogle(string postcode)
        {
            var longlat = new List<string>();
            var req = (HttpWebRequest)WebRequest.Create(string.Format("http://www.google.com/uds/GlocalSearch?q={0}&v=1.0", postcode));
            using (var resp = req.GetResponse())
            using (var respStream = resp.GetResponseStream())
            using (var reader = new StreamReader(respStream))
            {
                var response = reader.ReadToEnd();
                var serializer = new JavaScriptSerializer();
                var deserialized = (Dictionary<string, object>)serializer.DeserializeObject(response);
                var responseData = (Dictionary<string, object>)deserialized["responseData"];
                var results = (object[])responseData["results"];
                try
                {
                    var resultsData = (Dictionary<string, object>)results[0];
                    longlat.Add(resultsData["lat"].ToString());
                    longlat.Add(resultsData["lng"].ToString());
                    longlat.Add(resultsData["title"].ToString());
                }
                catch (Exception)
                {
                    longlat.Add("0");
                    longlat.Add("0");
                    longlat.Add("No Result");
                }
                return longlat;
            }
        }
    }
}