JS身份证验证

 1 window.checkIdcard = function (idcard) {
 2         var errors = new Array(
 3         "yes",
 4         "请检查输入的证件号码是否正确", //"身份证号码位数不对!",
 5         "请检查输入的证件号码是否正确", //"身份证号码出生日期超出范围或含有非法字符!",
 6         "请检查输入的证件号码是否正确", //"身份证号码校验错误!",
 7         "请检查输入的证件号码是否正确" //"身份证地区非法!"
 8         );
 9 
10         var area = { 11: "北京", 12: "天津", 13: "河北", 14: "山西", 15: "内蒙古", 21: "辽宁", 22: "吉林", 23: "黑龙江", 31: "上海", 32: "江苏", 33: "浙江", 34: "安徽", 35: "福建", 36: "江西", 37: "山东", 41: "河南", 42: "湖北", 43: "湖南", 44: "广东", 45: "广西", 46: "海南", 50: "重庆", 51: "四川", 52: "贵州", 53: "云南", 54: "西藏", 61: "陕西", 62: "甘肃", 63: "青海", 64: "宁夏", 65: "新疆", 71: "台湾", 81: "香港", 82: "澳门", 91: "国外" }
11         var y, jym;
12         var s, m;
13         var idcardArray = new Array();
14         idcard = idcard.replace(/(^\s*)|(\s*$)/g, "");
15 
16         idcardArray = idcard.split("");
17         //地区检验 
18         if (area[parseInt(idcard.substr(0, 2))] == null) return errors[4];
19         //身份号码位数及格式检验 
20         var ereg;
21         switch (idcard.length) {
22             case 15:
23                 if ((parseInt(idcard.substr(6, 2)) + 1900) % 4 == 0 || ((parseInt(idcard.substr(6, 2)) + 1900) % 100 == 0 && (parseInt(idcard.substr(6, 2)) + 1900) % 4 == 0)) {
24                     ereg = /^[1-9][0-9]{5}[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|[1-2][0-9]))[0-9]{3}$/; //测试出生日期的合法性 
25                 } else {
26                     ereg = /^[1-9][0-9]{5}[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|1[0-9]|2[0-8]))[0-9]{3}$/; //测试出生日期的合法性 
27                 }
28                 if (ereg.test(idcard)) return errors[0];
29                 else return errors[2];
30             case 18:
31                 //18位身份号码检测 
32                 //出生日期的合法性检查  
33                 //闰年月日:((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|[1-2][0-9])) 
34                 //平年月日:((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|1[0-9]|2[0-8])) 
35                 if (parseInt(idcard.substr(6, 4)) % 4 == 0 || (parseInt(idcard.substr(6, 4)) % 100 == 0 && parseInt(idcard.substr(6, 4)) % 4 == 0)) {
36                     ereg = /^[1-9][0-9]{5}(19|20)[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|[1-2][0-9]))[0-9]{3}[0-9Xx]$/; //闰年出生日期的合法性正则表达式 
37                 } else {
38                     ereg = /^[1-9][0-9]{5}(19|20)[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|1[0-9]|2[0-8]))[0-9]{3}[0-9Xx]$/; //平年出生日期的合法性正则表达式 
39                 }
40                 if (ereg.test(idcard)) {//测试出生日期的合法性 
41                     //计算校验位 
42                     s = (parseInt(idcardArray[0]) + parseInt(idcardArray[10])) * 7
43                     + (parseInt(idcardArray[1]) + parseInt(idcardArray[11])) * 9
44                     + (parseInt(idcardArray[2]) + parseInt(idcardArray[12])) * 10
45                     + (parseInt(idcardArray[3]) + parseInt(idcardArray[13])) * 5
46                     + (parseInt(idcardArray[4]) + parseInt(idcardArray[14])) * 8
47                     + (parseInt(idcardArray[5]) + parseInt(idcardArray[15])) * 4
48                     + (parseInt(idcardArray[6]) + parseInt(idcardArray[16])) * 2
49                     + parseInt(idcardArray[7]) * 1
50                     + parseInt(idcardArray[8]) * 6
51                     + parseInt(idcardArray[9]) * 3;
52                     y = s % 11;
53                     m = "F";
54                     jym = "10X98765432";
55                     m = jym.substr(y, 1); //判断校验位
56                     if (m == idcardArray[17]) return errors[0]; //检测ID的校验位 
57                     else return errors[3];
58                 }
59                 else return errors[2];
60             default:
61                 return errors[1];
62         }
63     }

.NET后台验证点这里

转载于:https://www.cnblogs.com/liuxiaoji/p/4533927.html