[LeetCode] #8 String to Integer (atoi)

最新推荐文章于 2025-09-10 15:24:29 发布

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最新推荐文章于 2025-09-10 15:24:29 发布

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文章标签：数据结构与算法

原文链接：http://www.cnblogs.com/Scorpio989/p/4413790.html

本文介绍了一种将字符串转换为整数的方法，并通过C++代码实现了一个atoi函数。该函数考虑了各种输入情况，包括正负号处理、空格忽略及整数溢出检查。

Implement atoi to convert a string to an integer.

Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases.

Notes: It is intended for this problem to be specified vaguely (ie, no given input specs). You are responsible to gather all the input requirements up front.

题目不难，一样要注意int的边界问题。时间：19ms

代码如下：

class Solution {
public:
    int atoi(string str) {
        if (str.size() == 0)
            return  0;
        bool sign = false;
        long long num = 0;
        string::const_iterator iter = str.begin();
        while (iter != str.end() && *iter == ' '){ ++iter; }
        if (iter == str.end())
            return 0;
        if (*iter == '+' || *iter == '-'){
            if (*iter == '-')
                sign = true;
            iter++;
        }
        while (iter != str.end()){
            if (*iter >= '0'&&*iter <= '9'){
                num = num * 10 + *iter - '0';
                if (num > 2147483648){
                    num = 2147483648;
                    break;
                }
            }
            else
                break;
            ++iter;
        }
        if (sign == true)
            num = 0 - num;
        else if (num == 2147483648)
            num--;
        return num;
    }
};