C# 发送和接受Get请求

weixin_30375427

于 2014-09-18 17:45:00 发布

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原文链接：http://www.cnblogs.com/tianxue/p/3979730.html

本文介绍了如何使用C#实现HTTP GET请求的发送与接收。发送GET请求时，通过构造HttpWebRequest并设置相应属性来完成请求，同时展示了如何读取响应内容。在接收GET请求方面，演示了如何从QueryString中获取参数。

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1、发送Get请求

    　　public static string HttpGet(string Url, string postDataStr)
        {
            HttpWebRequest request = (HttpWebRequest)WebRequest.Create(Url + (postDataStr == string.Empty ? string.Empty : "?") + postDataStr);
            request.Method = "GET";
            request.ContentType = "text/html;charset=UTF-8";

            HttpWebResponse response = (HttpWebResponse)request.GetResponse();
            Stream myResponseStream = response.GetResponseStream();
            StreamReader myStreamReader = new StreamReader(myResponseStream, Encoding.GetEncoding("utf-8"));
            string retString = myStreamReader.ReadToEnd();
            myStreamReader.Close();
            myResponseStream.Close();

            return retString;
        }

2、接受Get请求

string str1 = HttpUtility.UrlDecode(this.Request.QueryString.ToString(), Encoding.UTF8);

转载于:https://www.cnblogs.com/tianxue/p/3979730.html