pat1005. Spell It Right (20)

最新推荐文章于 2022-05-13 11:38:51 发布

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最新推荐文章于 2022-05-13 11:38:51 发布

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原文链接：http://www.cnblogs.com/Deribs4/p/4663470.html

本文介绍了一个使用C++解决的问题：给定一个非负整数N，计算其各位数字之和，并将每个数字以英文单词形式输出。程序包括输入处理、求和逻辑、以及将数字转换为英文单词的输出方法。

1005. Spell It Right (20)

时间限制

400 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.

Input Specification:

Each input file contains one test case. Each case occupies one line which contains an N (<= 10¹⁰⁰).

Output Specification:

For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.

Sample Input:

Sample Output:

one five

 1 #include <cstdio>
 2 #include <cstring>
 3 #include <string>
 4 #include <queue>
 5 #include <stack>
 6 #include <iostream>
 7 using namespace std;
 8 string digits[15]={"zero","one","two","three","four","five","six","seven","eight","nine"};
 9 int main(){
10     string ss;
11     int sum=0,i=0,csum=0;
12     cin>>ss;
13     while(i<ss.length()){
14         sum+=ss[i++]-'0';
15     }
16     if(!sum){
17         cout<<digits[sum]<<endl;
18         return 0;
19     }
20     stack<string> s;
21     while(sum){
22         s.push(digits[sum%10]);
23         sum/=10;
24     }
25     cout<<s.top();
26     s.pop();
27     while(!s.empty()){
28         cout<<" "<<s.top();
29         s.pop();
30     }
31     return 0;
32 }