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本文介绍了一个关于如何最小化教学时间的问题。Devu需要学习n门课程，每门课程有不同的章节数。通过合理安排课程顺序，可以减少总的教学时间。文章提供了一种贪心算法解决方案，并附带了代码实现。

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Devu, the Dumb Guy

Devu is a dumb guy, his learning curve is very slow. You are supposed to teach him nsubjects, the i^th subject has c_i chapters. When you teach him, you are supposed to teach all the chapters of a subject continuously.

Let us say that his initial per chapter learning power of a subject is x hours. In other words he can learn a chapter of a particular subject in x hours.

Well Devu is not complete dumb, there is a good thing about him too. If you teach him a subject, then time required to teach any chapter of the next subject will require exactly 1 hour less than previously required (see the examples to understand it more clearly). Note that his per chapter learning power can not be less than 1 hour.

You can teach him the n subjects in any possible order. Find out minimum amount of time (in hours) Devu will take to understand all the subjects and you will be free to do some enjoying task rather than teaching a dumb guy.

Please be careful that answer might not fit in 32 bit data type.

Input

The first line will contain two space separated integers n, x (1 ≤ n, x ≤ 10⁵). The next line will contain n space separated integers: c₁, c₂, ..., c_n (1 ≤ c_i ≤ 10⁵).

Output

Output a single integer representing the answer to the problem.

Examples

Input

2 3
4 1

Output

Input

4 2
5 1 2 1

Output

Input

3 3
1 1 1

Output

Note

Look at the first example. Consider the order of subjects: 1, 2. When you teach Devu the first subject, it will take him 3 hours per chapter, so it will take 12 hours to teach first subject. After teaching first subject, his per chapter learning time will be 2 hours. Now teaching him second subject will take 2 × 1 = 2 hours. Hence you will need to spend 12 + 2 = 14 hours.

Consider the order of subjects: 2, 1. When you teach Devu the second subject, then it will take him 3 hours per chapter, so it will take 3 × 1 = 3 hours to teach the second subject. After teaching the second subject, his per chapter learning time will be 2 hours. Now teaching him the first subject will take 2 × 4 = 8 hours. Hence you will need to spend 11 hours.

So overall, minimum of both the cases is 11 hours.

Look at the third example. The order in this example doesn't matter. When you teach Devu the first subject, it will take him 3 hours per chapter. When you teach Devu the second subject, it will take him 2 hours per chapter. When you teach Devu the third subject, it will take him 1 hours per chapter. In total it takes 6 hours.

sol：较显然的贪心，从小到大排序后先学小的再学大的

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
inline ll read()
{
    ll s=0;
    bool f=0;
    char ch=' ';
    while(!isdigit(ch))
    {
        f|=(ch=='-'); ch=getchar();
    }
    while(isdigit(ch))
    {
        s=(s<<3)+(s<<1)+(ch^48); ch=getchar();
    }
    return (f)?(-s):(s);
}
#define R(x) x=read()
inline void write(ll x)
{
    if(x<0)
    {
        putchar('-'); x=-x;
    }
    if(x<10)
    {
        putchar(x+'0'); return;
    }
    write(x/10);
    putchar((x%10)+'0');
    return;
}
#define W(x) write(x),putchar(' ')
#define Wl(x) write(x),putchar('\n')
const int N=100005;
int n;
long long X,A[N];
int main()
{
    int i;
    ll ans=0;
    R(n); R(X);
    for(i=1;i<=n;i++) R(A[i]);
    sort(A+1,A+n+1);
    for(i=1;i<=n;i++)
    {
        ans+=1ll*X*A[i];
        if(X>1) X--;
    }
    Wl(ans);
    return 0;
}
/*
input
2 3
4 1
output
11

input
4 2
5 1 2 1
output
10

input
3 3
1 1 1
output
6
*/