数位dp。。。要求不含49。dp[i][0]表示不含,dp[i][1]表示i位为6,dp[i][2]表示含。(long long 啊最近总是被long long坑啊!!!
#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
using namespace std;
#define rep(i,s,t) for(int i=s;i<=t;i++)
#define dwn(i,s,t) for(int i=s;i>=t;i--)
#define clr(x,c) memset(x,c,sizeof(x))
#define ll long long
ll read(){
ll x=0;char c=getchar();
while(!isdigit(c)) c=getchar();
while(isdigit(c)) x=x*10+c-'0',c=getchar();
return x;
}
const int nmax=25;
ll dp[nmax][3];int bit[nmax];
void init(){
clr(dp,0);dp[0][0]=1;
rep(i,1,20) {
dp[i][0]=dp[i-1][0]*10-dp[i-1][1];
dp[i][1]=dp[i-1][0];
dp[i][2]=dp[i-1][2]*10+dp[i-1][1];
}
}
ll work(ll x){
ll tmp=x,ans=0;int cnt=0;
while(tmp) bit[++cnt]=tmp%10,tmp/=10;
bit[cnt+1]=0;bool flag=false;
dwn(i,cnt,1){
ans+=bit[i]*dp[i-1][2];
if(flag) ans+=bit[i]*dp[i-1][0];
else if(bit[i]>4) ans+=dp[i-1][1];
if(bit[i+1]==4&&bit[i]==9) flag=true;
}
return ans;
}
int main(){
ll cas=read();init();
while(cas--){
ll tmp=read();
printf("%lld\n",work(tmp+1));
}
return 0;
}
upd:记忆化搜索版。代码量比较少。
#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
using namespace std;
#define rep(i,s,t) for(int i=s;i<=t;i++)
#define dwn(i,s,t) for(int i=s;i>=t;i--)
#define ll long long
#define clr(x,c) memset(x,c,sizeof(x))
ll read(){
ll x=0;char c=getchar();bool f=true;
while(!isdigit(c)){
if(c=='-') f=false;c=getchar();
}
while(isdigit(c)) x=x*10+c-'0',c=getchar();
return f?x:-x;
}
ll dp[25][3];
int cnt,bit[25];
ll work(int cur,int op,bool flag){
if(!cur) return op==0;
if(!flag&&dp[cur][op]!=-1) return dp[cur][op];
ll ans=0;int end=flag?bit[cur]:9;
rep(i,0,end){
int tmp=op;
if(op==1&&i==9) tmp=0;
if(op==2&&i==4) tmp=1;
if(op==1&&i!=9&&i!=4) tmp=2;
ans+=work(cur-1,tmp,flag&&i==end);
}
if(!flag) dp[cur][op]=ans;
return ans;
}
void getbit(ll x){
cnt=0;
while(x) bit[++cnt]=x%10,x/=10;
}
int main(){
ll cas=read();
while(cas--){
clr(dp,-1);
ll n=read();getbit(n);
printf("%lld\n",work(cnt,2,1));
}
return 0;
}