Complex Number Multiplication

最新推荐文章于 2021-08-25 20:26:42 发布

转载最新推荐文章于 2021-08-25 20:26:42 发布 · 56 阅读

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原文链接：http://www.cnblogs.com/spyder13/p/7436430.html

本文提供了一个Java程序示例，用于实现两个复数的乘法运算。通过解析输入字符串，提取实部和虚部，然后根据复数乘法规则进行计算，并输出结果。

public class ComplexNumberMultiplicationSolution {
    public static String complexNumberMultiply(String a, String b) {
        int p1 = Integer.parseInt(a.split("\\+")[0]);
        int n1 = Integer.parseInt(a.split("\\+")[1].split("i")[0]);
        int p2 = Integer.parseInt(b.split("\\+")[0]);
        int n2 = Integer.parseInt(b.split("\\+")[1].split("i")[0]);
        int p = p1 * p2 - n1 * n2;
        int n = p1 * n2 + p2 * n1;
        String strP = String.valueOf(p);
        String strN = String.valueOf(n);
        System.out.println(p1);
        System.out.println(n1);
        System.out.println(p2);
        System.out.println(n2);
        System.out.println(strP + "+" + strN + "i");
        return null;
    }

    public static void main(String[] args) {
        ComplexNumberMultiplicationSolution complexNumberMultiplicationSolution = new ComplexNumberMultiplicationSolution();
        complexNumberMultiplicationSolution.complexNumberMultiply("1+2i", "3+4i");
    }
}