1001. A+B Format (20)-优快云博客

本文介绍了一个简单的编程问题：计算两个整数a和b的和，并将结果以标准格式输出，即使用逗号作为千位分隔符。文章通过示例输入和输出展示了如何实现这一功能，并提供了完整的C语言代码。

1001. A+B Format (20)

Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input

Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.

Output

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input

-1000000 9

Sample Output

-999,991

简单题，不过真的很久没有写代码了，手真是残，从今天正式开始刷题啦，思路直接看代码

#include<stdio.h>
#include<string.h>
#include<math.h>
int main()
{
    int a, b, x[100], i; int c;
    while (scanf("%d%d",&a,&b) != EOF)
    {
        memset(x, 0, sizeof(x));
        c = a + b;
        i = 0;
        while (c / 1000 != 0)
        {
            x[i++] = c% 1000;
            c /= 1000;
        }
        x[i] = c%1000;
        if (c < 0) printf("-");
        int j;
        if(i>0)
        for (j = i; j >=0; j--)
        {
            int h= abs(x[j]);
            if (j != i)
            {
               if(h >= 0 && h <= 9) printf("00%d", h);
               else if (h >= 10 && h <= 99) printf("0%d", h);
               else printf("%d", h);
               if (j != 0) printf(",");
            }
            else printf("%d,",h);
        } 
        else printf("%d\n", abs(x[i]));    
    }
}