Search in Rotated Sorted Array

public class Solution {
    public int search(int[] A, int target) {
        if(A==null || A.length==0)
            return -1;
        int l = 0;
        int r = A.length-1;
        while(l<=r)
        {
            int m = (l+r)/2;
            if(target == A[m])
                return m;
            if(A[m]<A[r])
            {
                if(target>A[m] && target<=A[r])
                    l = m+1;
                else
                    r = m-1;
            }
            else
            {
                if(target>=A[l] && target<A[m])
                    r = m-1;
                else
                    l = m+1;                    
            }
        }
        return -1;
    }
}

 

转载于:https://www.cnblogs.com/jiajiaxingxing/p/4421298.html