先横着切m-1刀,矩形巧克力就变成了1*n (有m个)然后每个都要切n-1下,所以有 m*(n-1) +(m-1)= n*m-1
#include<cstdio>
int main()
{
int n,m;
while(scanf("%d%d",&n,&m)!=EOF)
{
printf("%d\n",n*m-1);
}
}
先横着切m-1刀,矩形巧克力就变成了1*n (有m个)然后每个都要切n-1下,所以有 m*(n-1) +(m-1)= n*m-1
#include<cstdio>
int main()
{
int n,m;
while(scanf("%d%d",&n,&m)!=EOF)
{
printf("%d\n",n*m-1);
}
}
转载于:https://www.cnblogs.com/murmured/p/5004303.html