ZigZag Conversion

最新推荐文章于 2024-10-24 22:31:46 发布

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最新推荐文章于 2024-10-24 22:31:46 发布

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原文链接：http://www.cnblogs.com/bingo2-here/p/7353486.html

本文介绍了一种将字符串以Z形排列方式写入指定行数的方法，并提供了完整的Java代码实现。该方法首先将字符串按Z形模式分配到不同的行中，然后逐行读取并拼接成最终的转换结果。

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The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)

P   A   H   N
A P L S I I G
Y   I   R

And then read line by line:

"PAHNAPLSIIGYIR"

Write the code that will take a string and make this conversion given a number of rows:

string convert(string text, int nRows);

convert("PAYPALISHIRING", 3)

should return

"PAHNAPLSIIGYIR"

public String convert(String s, int numRows) {
        char[] c = s.toCharArray();
        int len = c.length;
        StringBuilder[] stringBuilders=new StringBuilder[numRows];
        for (int i=0;i<numRows;i++){
            stringBuilders[i] = new StringBuilder();
        }
        int i=0;
        while(i<len){
            for (int idx=0;idx<numRows&&i<len;idx++){//自顶向下保存字符
                stringBuilders[idx].append(c[i++]);
            }
            for (int idx=numRows-2;idx>=1&&i<len;idx--){//向上保存字符
                stringBuilders[idx].append(c[i++]);
            }
        }
        for (i=1;i<numRows;i++){
            stringBuilders[0].append(stringBuilders[i]);
        }
        return stringBuilders[0].toString();
    }

转载于:https://www.cnblogs.com/bingo2-here/p/7353486.html