Integer to English Words

本文介绍了一种将非负整数转换为其英文单词表示的方法。该方法能够处理小于2^31 - 1的整数,并通过递归方式构建英文单词。文章提供了详细的Java代码实现。

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Convert a non-negative integer to its english words representation. Given input is guaranteed to be less than 231 - 1.

For example,

123 -> "One Hundred Twenty Three"
12345 -> "Twelve Thousand Three Hundred Forty Five"
1234567 -> "One Million Two Hundred Thirty Four Thousand Five Hundred Sixty Seven"

 1 public class Solution {
 2   private final String[] belowTwenty = new String[] {"", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Eleven", 
 3           "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen"};
 4   private final String[] belowHundred = new String[] {"", "", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety"};
 5   
 6   public String numberToWords(int num) {
 7       if (num == 0) {
 8           return "Zero";
 9       }
10       return helper(num);
11   }
12 
13   private String helper(int num) {
14       String result = new String();
15       if (num < 20) { result = belowTwenty[num]; }
16       else if (num < 100) { result = belowHundred[num / 10] + " " + helper(num % 10); }
17       else if (num < 1000) { result = helper(num / 100) + " Hundred " +  helper(num % 100); }
18       else if (num < 1000000) { result = helper(num / 1000) + " Thousand " +  helper(num % 1000); }
19       else if (num < 1000000000) { result = helper(num / 1000000) + " Million " +  helper(num % 1000000); }
20       else result = helper(num / 1000000000) + " Billion " + helper(num % 1000000000);
21       return result.trim();
22   }
23 }

Reference:

http://blog.welkinlan.com/2015/09/29/integer-to-english-words-leetcode-java/

转载于:https://www.cnblogs.com/beiyeqingteng/p/5713295.html

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