HDOJ 1062 Text Reverse

本文介绍了如何通过编程实现逆序单词的文本处理过程,包括输入解析、逆序操作及输出展示,适用于Java语言。

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Text Reverse

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 12577    Accepted Submission(s): 4743


Problem Description
Ignatius likes to write words in reverse way. Given a single line of text which is written by Ignatius, you should reverse all the words and then output them.
 

Input
The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains a single line with several words. There will be at most 1000 characters in a line.
 

Output
For each test case, you should output the text which is processed.
 

Sample Input
3
olleh !dlrow
m'I morf .udh
I ekil .mca
 

Sample Output
hello world!
I'm from hdu.
I like acm.
Hint
Remember to use getchar() to read '\n' after the interger T, then you may use gets() to read a line and process it.
 

Author
Ignatius.L
 




#include <iostream>
#include <cstdio>
#include <cstring>
#include <stack>

using namespace std;
char str[1000];

int main()
{
    int T;
    cin>>T;
    getchar();
while(T--)
{
    stack<char> st;
    gets(str);
    int len=strlen(str);
    int i;


    str[len]=' ';
    for(i=0;i<=len;i++)
    {
        if(str!=' ')
        {

           st.push(str);
        }
        else  if(str==' ')
        {

            while(!st.empty())
            {
                cout<<st.top();
                st.pop();
            }
            if(i!=len)
            cout<<" ";
            else
            cout<<endl;

        }

    }

}

    return 0;
}

 

转载于:https://www.cnblogs.com/CKboss/p/3351006.html

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