[分享]转换金额为人民币大写代码

最新推荐文章于 2024-08-06 14:53:17 发布

转载最新推荐文章于 2024-08-06 14:53:17 发布 · 73 阅读

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原文链接：http://www.cnblogs.com/beniao/articles/1273694.html

本文介绍了一种将数值金额转换为人民币大写形式的方法。通过定义数字和单位对应的字符串数组，实现了从数值到汉字的映射。该方法适用于财务系统中金额的规范化表示。

         /// <summary>
        /// 转换金额为人民币大写
        /// </summary>
        /// <param name="n">Int64 金额</param>
        /// <returns>人民币大写</returns>
        public static string ToRMB(double dn)
        {
            string[] strN = { "0", "1", "2", "3", "4", "5", "6", "7", "8", "9" };
            string[] strC = { "零", "壹", "贰", "叁", "肆", "伍", "陆", "柒", "捌", "玖" };
            string[] strA = { "", "圆", "拾", "佰", "仟", "万", "拾", "佰", "仟", "亿", "拾", "佰", "仟", "万亿", "拾", "佰", "仟", "亿亿", };
            int[] nLoc = { 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0 };

            string strFrom = "";
            string strTo = "";
            string strChar;
            int m, mLast = -1, nCount = 0;

if (strFrom.Length > strA.GetUpperBound(0) - 1) return "***拜托，这么多钱还需要数吗***";

            if (dn < 0)
            {
                dn *= -1;
                strTo = "负";
            }

Int64 n1 = (Int64)dn; // 元
strFrom = n1.ToString();

            for (int i = strFrom.Length; i > 0; i--)
            {
                strChar = strFrom.Substring(strFrom.Length - i, 1);
                m = Convert.ToInt32(strChar);
                if (m == 0)
                {
                    // 连续为０时需要补齐中间单位,且只补第一次
                    if (nLoc[i] > 0 && nCount == 0 && strFrom.Length > 1)
                    {
                        strTo = strTo + strA[i];
                        nCount++;
                    }
                }
                else
                {
                    // 补０
                    if (mLast == 0)
                    {
                        strTo = strTo + strC[0];
                    }

                    // 数字转换为大写
                    strTo = strTo + strC[m];
                    // 补足单位
                    strTo = strTo + strA[i];
                    nCount = 0;
                }
                mLast = m;
            }

            Int64 n2 = ((Int64)(dn * 100)) % 100;   // 角分
            Int64 n3 = n2 / 10;                     // 角
            Int64 n4 = n2 % 10;                     // 分
            string s2 = "";

            if (n4 > 0)
            {
                s2 = strC[n4] + "分";
                if (n3 > 0)
                {
                    s2 = strC[n3] + "角" + s2;
                }
            }
            else
            {
                if (n3 > 0)
                {
                    s2 = strC[n3] + "角";
                }
            }
            strTo = strTo + s2;

            if (strTo == "") strTo = strC[0];                   // 全0显示为零
            else if (s2 == "") strTo = strTo + "整";            // 无角分显示整
            return strTo;
        }

转载于:https://www.cnblogs.com/beniao/articles/1273694.html