Codeforces Round #397 by Kaspersky Lab and Barcelona Bootcamp (Div. 1 + Div. 2 combined) A - Neveren...

CodeForces A题解析
本文解析了CodeForces竞赛中A题“Neverending competitions”的背景及解题思路。介绍了团队Jinotega参加斯诺克比赛的行程特点,并通过分析飞行记录来判断团队当前是否在家或参加远地比赛。

地址:http://codeforces.com/contest/765/problem/A

题目:

A. Neverending competitions
time limit per test
2 seconds
memory limit per test
512 megabytes
input
standard input
output
standard output

There are literally dozens of snooker competitions held each year, and team Jinotega tries to attend them all (for some reason they prefer name "snookah")! When a competition takes place somewhere far from their hometown, Ivan, Artsem and Konstantin take a flight to the contest and back.

Jinotega's best friends, team Base have found a list of their itinerary receipts with information about departure and arrival airports. Now they wonder, where is Jinotega now: at home or at some competition far away? They know that:

  • this list contains all Jinotega's flights in this year (in arbitrary order),
  • Jinotega has only flown from his hometown to a snooker contest and back,
  • after each competition Jinotega flies back home (though they may attend a competition in one place several times),
  • and finally, at the beginning of the year Jinotega was at home.

Please help them to determine Jinotega's location!

Input

In the first line of input there is a single integer n: the number of Jinotega's flights (1 ≤ n ≤ 100). In the second line there is a string of 3capital Latin letters: the name of Jinotega's home airport. In the next n lines there is flight information, one flight per line, in form "XXX->YYY", where "XXX" is the name of departure airport "YYY" is the name of arrival airport. Exactly one of these airports is Jinotega's home airport.

It is guaranteed that flights information is consistent with the knowledge of Jinotega's friends, which is described in the main part of the statement.

Output

If Jinotega is now at home, print "home" (without quotes), otherwise print "contest".

Examples
input
4
SVO
SVO->CDG
LHR->SVO
SVO->LHR
CDG->SVO
output
home
input
3
SVO
SVO->HKT
HKT->SVO
SVO->RAP
output
contest
Note

In the first sample Jinotega might first fly from SVO to CDG and back, and then from SVO to LHR and back, so now they should be at home. In the second sample Jinotega must now be at RAP because a flight from RAP back to SVO is not on the list.

 

思路:因为输入的情况必定合法,所以可以用n的奇偶性判断是home还是contest

 1 #include <bits/stdc++.h>
 2 
 3 using namespace std;
 4 
 5 #define MP make_pair
 6 #define PB push_back
 7 typedef long long LL;
 8 typedef pair<int,int> PII;
 9 const double eps=1e-8;
10 const double pi=acos(-1.0);
11 const int K=1e5+7;
12 const int mod=1e9+7;
13 
14 int n;
15 int main(void)
16 {
17     cin>>n;
18     if(n&1)
19         printf("contest\n");
20     else
21         printf("home\n");
22     return 0;
23 }

 

转载于:https://www.cnblogs.com/weeping/p/6420907.html

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