关于UI_USER_INTERFACE_IDIOM() & UIDevice.model

最新推荐文章于 2021-04-03 13:36:28 发布

转载最新推荐文章于 2021-04-03 13:36:28 发布 · 233 阅读

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CC 4.0 BY-SA版权

原文链接：http://www.cnblogs.com/hualuoshuijia/p/6022744.html

文章标签：

#ui #5g

本文介绍了几种在iOS应用中区分不同设备类型的方法，包括使用UI_USER_INTERFACE_IDIOM、UIDevice.model以及通过sysctlbyname获取设备名称等。适用于iOS开发者在开发过程中根据不同设备特性进行适配。

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使用  UI_USER_INTERFACE_IDIOM() 进行区分  (ios 3.2 >=)  无法区分iphone和ipod
 
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) {
       // <define your constants here>
    } else {
      //  <define your constants here>
    }
 
区分目前UI_USER_INTERFACE_IDIOM()有2个返回值
UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad    

UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone    

 
使用 UIDevice.model 进行区分  (ios 2.0 >=)
 
    NSString *deviceType = [UIDevice currentDevice].model;
    
    if([deviceType isEqualToString:@"iPhone"]) {
        //iPhone
    }
    else if([deviceType isEqualToString:@"iPod touch"]) {
        //iPod Touch
    }
    else {
        //iPad
    }

 
使用系统的一个函数sysctlbyname 来获取设备名称

- (NSString *) platformString
{
    size_t size;
    sysctlbyname("hw.machine", NULL, &size, NULL, 0);
    char *machine = malloc(size);
    sysctlbyname("hw.machine", machine, &size, NULL, 0);
    NSString *platform = [NSString stringWithUTF8String:machine];
    free(machine);
    if ([platform isEqualToString:@"iPhone1,1"])    return @"iPhone 1G";
    if ([platform isEqualToString:@"iPhone1,2"])    return @"iPhone 3G";
    if ([platform isEqualToString:@"iPhone2,1"])    return @"iPhone 3GS";
    if ([platform isEqualToString:@"iPhone3,1"])    return @"iPhone 4";
    if ([platform isEqualToString:@"iPhone3,3"])    return @"Verizon iPhone 4";
    if ([platform isEqualToString:@"iPod1,1"])      return @"iPod Touch 1G";
    if ([platform isEqualToString:@"iPod2,1"])      return @"iPod Touch 2G";
    if ([platform isEqualToString:@"iPod3,1"])      return @"iPod Touch 3G";
    if ([platform isEqualToString:@"iPod4,1"])      return @"iPod Touch 4G";
    if ([platform isEqualToString:@"iPad1,1"])      return @"iPad";
    if ([platform isEqualToString:@"iPad2,1"])      return @"iPad 2 (WiFi)";
    if ([platform isEqualToString:@"iPad2,2"])      return @"iPad 2 (GSM)";
    if ([platform isEqualToString:@"iPad2,3"])      return @"iPad 2 (CDMA)";
    if ([platform isEqualToString:@"i386"])         return @"Simulator";
    return @"";
}

在添加一些收集到的
//iPhone
    if ([deviceString isEqualToString:@"iPhone4,1"])    return @"iPhone 4S";
    if ([deviceString isEqualToString:@"iPhone5,1"])    return @"iPhone 5(AT&T)";
    if ([deviceString isEqualToString:@"iPhone5,2"])    return @"iPhone 5(GSM/CDMA)";
//iPod Touch
    if ([deviceString isEqualToString:@"iPod5,1"])      return @"iPod Touch 5G";
//iPad
    if ([deviceString isEqualToString:@"iPad2,5"])      return @"iPad Mini (WiFi)";
    if ([deviceString isEqualToString:@"iPad2,6"])      return @"iPad Mini (GSM)";
    if ([deviceString isEqualToString:@"iPad2,7"])      return @"iPad Mini (CDMA)";
    if ([deviceString isEqualToString:@"iPad3,1"])      return @"iPad 3 (WiFi)";
    if ([deviceString isEqualToString:@"iPad3,2"])      return @"iPad 3 (GSM)";
    if ([deviceString isEqualToString:@"iPad3,3"])      return @"iPad 3 (CDMA)";
    if ([deviceString isEqualToString:@"iPad3,4"])      return @"iPad 4 (WiFi)";
    if ([deviceString isEqualToString:@"iPad3,5"])      return @"iPad 4 (GSM)";
    if ([deviceString isEqualToString:@"iPad3,6"])      return @"iPad 4 (CDMA)";
//Simulator
    if ([deviceString isEqualToString:@"i386"])         return @"Simulator";
    if ([deviceString isEqualToString:@"x86_64"])       return @"Simulator";



转载的没有那么多个机型逐个实验.所以不敢保证都正确.

原出处：http://blog.sina.com.cn/s/blog_890a737301014fim.html

转载于:https://www.cnblogs.com/hualuoshuijia/p/6022744.html