Jquery ajax执行顺序 返回自定义错误信息

1.多个Ajax 在一个function中的执行顺序

   由于Jquery中的Ajax的async默认是true(异步请求),如果想一个Ajax执行完后再执行另一个Ajax, 需要把async=false就可以了.

 

          function TestAjax(){

            var UserName = $("#txtUserName").val();

            $.ajax(

            {

                url: "AjaxCheckUserName.htm",

                async: false,

                success: function (data) {

                    alert(data);

                }

            });

            alert('Test');

            $.ajax({

                url: "AjaxHandler.ashx",

                async: false,

                data: "UserName=" + UserName,

                success: function (data) {

                    $("#divAjax").html(data);

                },

                error: function (msg) {

                    alert(msg.responseText);

                }

            });

        }

 

2. 返回自定义错误

设置 StatusCode = 500,

触发Ajax的错误(error), 在接收到数据显示自定义信息

error: function (msg) {

                    alert(msg.responseText);

                } 

 

 context.Response.StatusCode = 500;  context.Response.Write("请输入用户名");

            string sUserName = context.Request.QueryString["UserName"];

            if (!string.IsNullOrEmpty(sUserName))

            {

                context.Response.Write(string.Format("Hello {0}!", sUserName));

            }

            else

            {

                context.Response.StatusCode = 500;

                context.Response.Write("请输入用户名");

            }

 

转载于:https://www.cnblogs.com/yangsoon/p/3199973.html