405. Convert a Number to Hexadecimal

整数转十六进制算法
本文介绍了一种将整数转换为十六进制字符串的算法,并特别关注负数使用补码表示的情况。该算法不依赖任何直接进行十六进制转换的库函数,通过位操作实现数字的转换。

Given an integer, write an algorithm to convert it to hexadecimal. For negative integer, two’s complement method is used.

Note:

  1. All letters in hexadecimal (a-f) must be in lowercase.
  2. The hexadecimal string must not contain extra leading 0s. If the number is zero, it is represented by a single zero character '0'; otherwise, the first character in the hexadecimal string will not be the zero character.
  3. The given number is guaranteed to fit within the range of a 32-bit signed integer.
  4. You must not use any method provided by the library which converts/formats the number to hex directly.

Example 1:

Input:
26

Output:
"1a"

Example 2:

Input:
-1

Output:
"ffffffff"

class Solution {
public:
    string toHex(int num) {
        char ma[]={'0','1','2','3','4','5','6','7','8','9','a','b','c','d','e','f'};
        string ans="";
        do{
            ans=ma[num & 15]+ans; //四位二进制转化成一个十六进制
            num>>=4;    //每次处理四位
        }while(num&&ans.size()<8);
        return ans;
    }
};

 

转载于:https://www.cnblogs.com/tsunami-lj/p/6639407.html

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