sizeof(void)有什么用-优快云博客

本文探讨了C语言中sizeof(void)的合法性及其返回值为1的原因，通过引用GNU文档解释了这一现象，并对比了C++中对此用法的不同处理方式。

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偶然发现在C中sizeof(void)是合法的，于是，对它的作用产生了疑问。查阅资料在GNU文档中发现如下解释：

In GNU C, addition and subtraction operations are supported on pointers to void and on pointers to functions. This is done by treating the size of a void or of a function as 1. A consequence of this is that sizeof is also allowed on void and on function types, and returns 1.

测试代码如下：

#include <stdio.h>

int main(int argc, char* argv[]) {
  printf("sizeof(void): %lu\n", sizeof(void));
  printf("sizeof(function): %lu\n", sizeof(main));
  return 0;
}

C语言中输出如下：

sizeof(void): 1
sizeof(function): 1

C++中sizeof(void)是不合法的，编译错误如下：

void_size.c: In function ‘int main(int, char**)’:
void_size.c:15: error: invalid application of ‘sizeof’ to a void type
void_size.c:16: error: ISO C++ forbids applying ‘sizeof’ to an expression of function type

References

1.http://gcc.gnu.org/onlinedocs/gcc-4.4.6/gcc/Pointer-Arith.html

转载于:https://www.cnblogs.com/hellogc/p/3374756.html