poj 2390 Bank Interest

最新推荐文章于 2018-02-20 12:03:29 发布

转载最新推荐文章于 2018-02-20 12:03:29 发布 · 137 阅读

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原文链接：http://www.cnblogs.com/w0w0/archive/2011/11/22/2258465.html

本文提供了一个简单的复利计算器程序，帮助用户了解如何计算多年投资后的总收益。程序接收利率、本金和投资年限作为输入，并输出最终金额。

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Bank Interest

Time Limit: 1000MS		Memory Limit: 65536K
Total Submissions: 11770		Accepted: 7008

Description

Farmer John made a profit last year! He would like to invest it well but wonders how much money he will make. He knows the interest rate R (an integer between 0 and 20) that is compounded annually at his bank. He has an integer amount of money M in the range 100..1,000,000. He knows how many years Y (range: 0..400) he intends to invest the money in the bank. Help him learn how much money he will have in the future by compounding the interest for each year he saves. Print an integer answer without rounding. Answers for the test data are guaranteed to fit into a signed 32 bit integer.

Input

* Line 1: Three space-separated integers: R, M, and Y

Output

* Line 1: A single integer that is the number of dollars FJ will have after Y years.

Sample Input

5 5000 4

Sample Output

Hint

INPUT DETAILS:

5% annual interest, 5000 money, 4 years

OUTPUT DETAILS:

Year 1: 1.05 * 5000 = 5250
Year 2: 1.05 * 5250 = 5512.5
Year 3: 1.05 * 5512.50 = 5788.125
Year 4: 1.05 * 5788.125 = 6077.53125
The integer part of 6077.53125 is 6077.

#include<iostream>
using namespace std;
int main()
{ 
double a, b, c;
int i;
     cin>>a>>b>>c;
     a=a/100;
     a+=1;
for(i=0;i<c;i++)
     {
          b=a*b;
     }
     cout<<int(b)<<endl;
return 0;
}

转载于:https://www.cnblogs.com/w0w0/archive/2011/11/22/2258465.html