(Easy) Guess Number Higher or Lower -LeetCode

Description:

We are playing the Guess Game. The game is as follows:

I pick a number from 1 to n. You have to guess which number I picked.

Every time you guess wrong, I'll tell you whether the number is higher or lower.

You call a pre-defined API guess(int num) which returns 3 possible results (-1, 1, or 0):

-1 : My number is lower
 1 : My number is higher
 0 : Congrats! You got it!

Example :

Input: n = 10, pick = 6
Output: 6

Solution:

Key algorithm used:  Binary Search: 

/* The guess API is defined in the parent class GuessGame.
   @param num, your guess
   @return -1 if my number is lower, 1 if my number is higher, otherwise return 0
      int guess(int num); */

public class Solution extends GuessGame {
    public int guessNumber(int n) {
        
        int start = 1; 
        int end = n; 
 
  
        while ( start< end ){
            
            int mid = start +(end - start)/2;
            
            if(guess(mid)== 1){
                start = mid+1; 
            }
            
            else if(guess(mid)==-1){
                end = mid; 
            }
            
            else if(guess(mid)==0){
                
                return mid;
            }
        }
    
        return start;
        
    }
}

 

转载于:https://www.cnblogs.com/codingyangmao/p/11447361.html