Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level).
For example:
Given binary tree {3,9,20,#,#,15,7}
,
3 / \ 9 20 / \ 15 7
return its level order traversal as:
[ [3], [9,20], [15,7] ]
用lev记录当前树到了第几层。
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<vector<int> > re;
vector<vector<int> > levelOrder(TreeNode *root) {
if(root == NULL)return re;
level(root,1);
return re;
}
void level(TreeNode *root, int lev)
{
if(root == NULL)return;
if(lev > re.size())
{
vector<int > temp;
re.push_back(temp);
}
re[lev-1].push_back(root->val);
level(root->left,lev+1);
level(root->right,lev+1);
}
};