android生成随机字符串,Android随机字符串生成器

我有个问题.

我想画一个随机的字符串这样的aXcFg3s2.

我做坏事

如何改变我的随机()

private String random;

private String charsEntered;

private EditText et;

private Button ok;

CaptchaInterface.OnCorrectListener mCorrectListener;

public void setOnCorrectListener(CaptchaInterface.OnCorrectListener listener) {

mCorrectListener = listener;

}

public TextCaptcha(Context context) {

super(context);

getWindow().requestFeature(Window.FEATURE_NO_TITLE);

}

public static String random() {

Random generator = new Random();

String x = (String) (generator.nextInt(96) + 32);

return x;

}

public void onCreate(Bundle icicle) {

setContentView(R.layout.main);

random = random();

TextView display = (TextView) findViewById(R.id.textView1);

display.setText("Random Number: " + random); // Show the random number

et = (EditText) findViewById(R.id.etNumbers);

ok = (Button) findViewById(R.id.button1);

ok.setOnClickListener(this);

}

public void onClick(View arg0) {

// TODO Auto-generated method stub

try {

charsEntered = et.getText().toString();

} catch (NumberFormatException nfe) {

Toast.makeText(et.getContext(), "Bla bla bla",

Toast.LENGTH_LONG).show();

}

if (random == charsEntered) {

Toast.makeText(et.getContext(), "Good!", Toast.LENGTH_LONG).show();

} else {

Toast.makeText(et.getContext(), "Bad!", Toast.LENGTH_LONG).show();

}

}