matlab 真假随机,使用matlab使用概率随机生成器

这是一个具有以下逻辑的解决方案：

最多生成3次失败，随机分配

确定步骤2中有多少次失败

让以前的失败更有可能再次失败

请注意，我认为它同样可能有0,1,2或3次失败。

nRuns = 5;

allRuns = zeros(nRuns,10); %# stores success and failure for all runs

%# (1) generate from 0 to 3 failures (each outcome is equally likely)

nFailures = randi([0 3],1);

tmp = randperm(10);

firstRun = tmp > nFailures

allRuns(1,:) = firstRun;

%# (2) decide how many failures occur in the 2nd run (each outcome is equally likely)

for iRun = 2:nRuns

%# as the loop has been added later

%# I use "2" to indicate any next run

nFailures2 = randi([0 3],1);

%# (3) give previous failures a higher chance to fail again

failIdx = find(~allRuns(iRun-1,:));

successIdx = find(allRuns(iRun-1,:));

%# 5x higher chance of failing for previous failures

failCandidates = [repmat(failIdx,1,5),successIdx];

failCandidatesRand = failCandidates(randperm(length(failCandidates)));

%# if you have R2012a or later

failCandidatesRand = unique(failCandidatesRand ,'stable');

toFail = failCandidatesRand (1:nFailures2);

%# alternatively, if you have R2011b or earlier

toFail = zeros(nFailures2,1);

toFail(1) = failCandidatesRand(1);

ii = 2;

kk = 2;

while ii < (nFailures2+1)

if ~any(toFail==failCandidatesRand(kk));

toFail(ii) = failCandidatesRand(kk);

ii = ii + 1;

end

kk = kk + 1;

end

%# write failures

nextRun= true(1,10);

nextRun(toFail) = false

allRuns(iRun,:) = nextRun;

end