selenium 鼠标悬浮,如何在Selenium 2 API中处理鼠标悬停

最新推荐文章于 2024-04-20 22:41:35 发布

转载最新推荐文章于 2024-04-20 22:41:35 发布 · 257 阅读

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这篇博客探讨了在使用Selenium进行自动化测试时遇到的一个挑战：如何处理短暂出现并快速消失的三级导航元素。作者分享了一段代码，尝试通过鼠标按下和移动来点击二级导航后迅速出现的三级导航，但遇到了ElementNotVisibleException。解决方案是使用Selenium的条件等待，确保元素可见后再进行点击操作，以避免此类异常。

String strPrimaryNav = "MEN";

String strSecondaryNav = "Shoes";

String strTertiaryNav = "Golf";

driver.findElement(By.linkText(strPrimaryNav)).click();

WebElement weSecNav = driver.findElement(By.className("secondaryButton").linkText(strSecondaryNav));

Mouse mouse = ((HasInputDevices) driver).getMouse();

mouse.mouseDown(((Locatable)weSecNav).getCoordinates());

//just trying with for loop as the tertiary popup disappears quickly and hence getting ElementNotVisible Exception

for (int i = 0 ; i< 2; i++){

mouse.mouseDown(((Locatable)weSecNav).getCoordinates());

//mouse.mouseMove(((Locatable)weSecNav).getCoordinates(), 0, 0 );

//WebElement weTerNav = driver.findElement(By.className("tertiaryButton").linkText(strTertiaryNav));

WebElement weTerNav = driver.findElement(By.linkText(strTertiaryNav));

boolean isSecDisplayed = ((RenderedWebElement)weTerNav).isDisplayed();

System.out.println("isDisplayed: " + isSecDisplayed);

System.out.println(" " + ((RenderedWebElement)weSecNav).getAttribute("href"));

System.out.println(" " + ((RenderedWebElement)weSecNav).getValueOfCssProperty("action"));

weTerNav.click();

}

I was trying the below code using selenium 2 but, the tertiary popup not stays long to click it and hence getting ElementNotVisible exception at Tertiary click.

解决方案

You can at least check that the element is visible before you send your click:

Selenium s = new WebDriverBackedSelenium( driver, URL );

s.waitForCondition( "!( document.getElementById('.....') === null )", "20000" );

s.click( .... );

This avoids the exception. I'm not sure there is a way to make the popup stay any longer than it should.