LeetCode Fizz Buzz

最新推荐文章于 2022-07-27 11:33:06 发布

原创最新推荐文章于 2022-07-27 11:33:06 发布 · 322 阅读

0 ·

CC 4.0 BY-SA版权

文章标签：

#leetcode #buzz

LeetCode 专栏收录该内容

46 篇文章

订阅专栏

本文提供了一个关于FizzBuzz问题的Python实现方案。该程序能够输出从1到指定数字n之间的字符串，其中3的倍数被替换为Fizz，5的倍数被替换为Buzz，同时为3和5的倍数则被替换为FizzBuzz。通过一个简单的for循环和条件判断实现了这一功能。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

Write a program that outputs the string representation of numbers from 1 to n.

But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and five output “FizzBuzz”.

Example:

n = 15,

Return:
[
“1”,
“2”,
“Fizz”,
“4”,
“Buzz”,
“Fizz”,
“7”,
“8”,
“Fizz”,
“Buzz”,
“11”,
“Fizz”,
“13”,
“14”,
“FizzBuzz”
]
Subscribe to see which companies asked this question.

class Solution(object):
    def fizzBuzz(self, n):
        """
        :type n: int
        :rtype: list[str]
        """
        res = []
        for i in xrange(1,n+1):
            if i%15 ==0:
                res.append("FizzBuzz")
            elif i%3 == 0:
                res.append("Fizz")
            elif i%5 ==0:
                res.append("Buzz")
            else:
                res.append(i)
        return res
if __name__ == '__main__':
    print Solution().fizzBuzz(15)