int *a;
int N;
scanf("%d", &N);
a = (int *) malloc(N * sizeof(int));
....
free(a);
动态分配数组
最新推荐文章于 2025-08-15 18:53:39 发布
int *a;
int N;
scanf("%d", &N);
a = (int *) malloc(N * sizeof(int));
....
free(a);